Latest articles by Syed Mujtaba Naqvi
Pokemon
Fortnite
Pokemon
Valorant
Pokemon
Pokemon Scarlet & Violet Legendary Raid battle: Shiny Rayquaza
Syed Mujtaba Naqvi
Pokemon fans are in for an exciting event as Pokemon Scarlet & Violet prepare to launch a Tera Raid Battle featuring the legendary Shiny Rayquaza. The raid battle is set to take place from December 19, 2024, to January 5, 2025. This gives players a chance to add this rare, shiny form of the Sky High Pokemon to their collection. The details surrounding the event have sparked much anticipation among …
Fortnite
Unlocking the Wavebreaker Pack in Fortnite: A simple guide
Syed Mujtaba Naqvi
The Wavebreaker Pack has made an exciting return to Fortnite after a long absence. Originally launched as a part of the Chapter 2 Season 1 Starter Pack, it quickly became a rare and highly sought-after item. If you missed out on it previously, now’s your chance to grab it before it disappears again. In this guide, we’ll walk you through how to get the Wavebreaker Pack, what’s included, and how …
Pokemon
Pokemon GO: Dynamax Drilbur arrives in the latest event
Syed Mujtaba Naqvi
Starting November 15, Pokemon GO players will have the chance to encounter a brand-new Dynamax Pokemon, Drilbur, as part of the Simply Groundbreaking event. This thrilling event, which runs until November 17, introduces a fresh layer of gameplay with Dynamax forms, adding a new level of strategy to Max Battles. Trainers level 31 and up also have the opportunity to earn extra rewards, making this event one of the most …
Valorant
Valorant: Here’s how to unlock free Arcane player cards
Syed Mujtaba Naqvi
To celebrate the much-anticipated release of Arcane Season 2, Valorant players have a chance to get exclusive player cards featuring iconic characters, Vi and Jinx, for free. Riot Games has made it easy for fans to earn these special cards with just a few simple steps. This article explains when these cards are available and the steps you need to take to add them to your collection. Related: Valorant Arcane …
